2 条题解
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正面构造要输出的东西
#include<bits/stdc++.h> using namespace std; int main(){ int n,i,j; cin>>n>>i>>j; //输出同一行的 for(int y=1;y<=n;y++) cout<<"("<<i<<","<<y<<") "; cout<<"\n"; // 输出同一列的 for(int x=1;x<=n;x++) cout<<"("<<x<<","<<j<<") "; cout<<"\n"; // 左上到右下对角线 int x,y; x=i,y=j; while(x-1>=1&&y-1>=1) { x--; y--; } while(x<=n&&y<=n) { cout<<"("<<x<<","<<y<<") "; x++,y++; } cout<<"\n"; // 左下到右上对角线 x=i,y=j; while(x+1<=n&&y-1>=1) { x++; y--; } while(x>=1&&x<=n&&y>=1&&y<=n) { cout<<"("<<x<<","<<y<<") "; x--,y++; } cout<<"\n"; return 0; } -
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33DAI LV 8 (1/1) @ 2022-12-24 10:31:25
枚举所有可能的位置，检查要不要输出
#include<bits/stdc++.h> using namespace std; int main(){ int n, x, y; cin>>n>>x>>y; //(x,y)同一行 for(int i=1;i<=n;i++)//枚举行 for(int j=1;j<=n;j++)//枚举列 { //第i行第j列 if(i==x) cout<<"("<<i<<","<<j<<")"<<" "; } cout<<"\n"; //(x,y)同一列 for(int i=1;i<=n;i++)//枚举行 for(int j=1;j<=n;j++)//枚举列 { //第i行第j列 if(j==y) cout<<"("<<i<<","<<j<<")"<<" "; } cout<<"\n"; //(x,y)左上到右下斜线 for(int i=1;i<=n;i++)//枚举行 for(int j=1;j<=n;j++)//枚举列 { //第i行第j列 if(x-y==i-j) cout<<"("<<i<<","<<j<<")"<<" "; } cout<<"\n"; //(x,y)左下到右上斜线 for(int i=n;i>=1;i--)//枚举行 for(int j=1;j<=n;j++)//枚举列 { //第i行第j列 if(x+y==i+j) cout<<"("<<i<<","<<j<<")"<<" "; } cout<<"\n"; return 0; }
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