1 条题解
-
0
二分
#include <bits/stdc++.h> using namespace std; const int MAXN = 100000; const int MAXM = 100000; int n, m; int a[MAXN + 5]; int b[MAXM + 5]; int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> n >> m; for (int i = 1; i <= n; i++) cin >> a[i]; for (int i = 1; i <= m; i++) cin >> b[i]; // work sort(a + 1, a + n + 1); long long ans = 0; for (int i = 1; i <= m; i++) { int pos = lower_bound(a + 1, a + n + 1, b[i]) - a; if (pos == 1) ans += abs(a[pos] - b[i]); else if (pos == n + 1) ans += abs(a[n] - b[i]); else ans += min(abs(a[pos] - b[i]), abs(a[pos - 1] - b[i])); } cout << ans << "\n"; return 0; }
双指针
#include <bits/stdc++.h> using namespace std; const int MAXN = 100000; const int MAXM = 100000; int n, m; int a[MAXN + 5]; int b[MAXM + 5]; int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> n >> m; for (int i = 1; i <= n; i++) cin >> a[i]; for (int i = 1; i <= m; i++) cin >> b[i]; // work sort(a + 1, a + n + 1); sort(b + 1, b + m + 1); long long ans = 0; int pos = 1; // a[pos]>=b[i] for (int i = 1; i <= m; i++) { while (pos <= n && a[pos] < b[i]) pos++; if (pos == 1) ans += abs(a[pos] - b[i]); else if (pos == n + 1) ans += abs(a[n] - b[i]); else ans += min(abs(a[pos] - b[i]), abs(a[pos - 1] - b[i])); } cout << ans << "\n"; return 0; }
- 1
信息
- ID
- 1318
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 8
- 标签
- 递交数
- 37
- 已通过
- 7
- 上传者