1 条题解
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0
#include <bits/stdc++.h> using namespace std; int n; int f[25][25]; int main() { cin >> n; for (int i = 1; i <= n; i++) for (int j = 1; j <= i; j++) if (j == 1 || j == i) f[i][j] = 1; else f[i][j] = f[i - 1][j - 1] + f[i - 1][j]; for (int i = 1; i <= n; i++) { for (int j = 1; j <= i; j++) cout << f[i][j] << " "; cout << "\n"; } return 0; }
- 1
信息
- ID
- 1304
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 3
- 标签
- 递交数
- 36
- 已通过
- 23
- 上传者