做法 1：离线运算

生成“暴力枚举代码”的代码

#include<bits/stdc++.h>
using namespace std;
int main()
{
	freopen("ans.cpp","w",stdout);
	cout<<"#include<bits/stdc++.h>\n";
	cout<<"using namespace std;\n";
	cout<<"int main(){\n";
	cout<<"	int cnt=0;\n";
	for(char c='a';c<='j';c++)
		cout<<"    for(int "<<c<<"=0;"<<c<<"<=9;"<<c<<"++)\n"; 
	cout<<"    {\n";
	for(char i='a';i<='j';i++)
		for(char j=i+1;j<='j';j++)
			cout<<"        if("<<i<<"=="<<j<<") continue;\n";
	cout<<"        int x=a*10000+b*1000+c*100+d*10+e;\n";
	cout<<"        int y=f*10000+g*1000+h*100+i*10+j;\n";
	cout<<"        if(x%y==0)\n";
	cout<<"            cnt++;\n";
	cout<<"    }\n";	
	cout<<"    cout<<cnt;\n";
	cout<<"    return 0;\n";
	cout<<"}\n";
	return 0;
}

暴力枚举

#include<bits/stdc++.h>
using namespace std;
int main(){
	int cnt=0;
    for(int a=0;a<=9;a++)
    for(int b=0;b<=9;b++)
    for(int c=0;c<=9;c++)
    for(int d=0;d<=9;d++)
    for(int e=0;e<=9;e++)
    for(int f=0;f<=9;f++)
    for(int g=0;g<=9;g++)
    for(int h=0;h<=9;h++)
    for(int i=0;i<=9;i++)
    for(int j=0;j<=9;j++)
    {
        if(a==b) continue;
        if(a==c) continue;
        if(a==d) continue;
        if(a==e) continue;
        if(a==f) continue;
        if(a==g) continue;
        if(a==h) continue;
        if(a==i) continue;
        if(a==j) continue;
        if(b==c) continue;
        if(b==d) continue;
        if(b==e) continue;
        if(b==f) continue;
        if(b==g) continue;
        if(b==h) continue;
        if(b==i) continue;
        if(b==j) continue;
        if(c==d) continue;
        if(c==e) continue;
        if(c==f) continue;
        if(c==g) continue;
        if(c==h) continue;
        if(c==i) continue;
        if(c==j) continue;
        if(d==e) continue;
        if(d==f) continue;
        if(d==g) continue;
        if(d==h) continue;
        if(d==i) continue;
        if(d==j) continue;
        if(e==f) continue;
        if(e==g) continue;
        if(e==h) continue;
        if(e==i) continue;
        if(e==j) continue;
        if(f==g) continue;
        if(f==h) continue;
        if(f==i) continue;
        if(f==j) continue;
        if(g==h) continue;
        if(g==i) continue;
        if(g==j) continue;
        if(h==i) continue;
        if(h==j) continue;
        if(i==j) continue;
        int x=a*10000+b*1000+c*100+d*10+e;
        int y=f*10000+g*1000+h*100+i*10+j;
        if(x%y==0)
            cnt++;
    }
    cout<<cnt;
    return 0;
}

本地运行暴力代码得到答案

#include<bits/stdc++.h>
using namespace std;
int main()
{
	cout << "281\n";
	return 0;
}

做法 2

$n$ 最多不会超过100，可以枚举 $abcde$ 与 $n$，生成 $fghij$，检测是否正确。

#include<bits/stdc++.h>
using namespace std;
int main()
{
	int cnt=0;
	for(int x=01234;x<=98765;x++)
	{
		for(int n=0;n<=100;n++)
		{
			int y = x * n;
			if(y<01234||y>98765)
				continue;
			int a=x/10000%10;
			int b=x/1000%10;
			int c=x/100%10;
			int d=x/10%10;
			int e=x%10;
			int f=y/10000%10;
			int g=y/1000%10;
			int h=y/100%10;
			int i=y/10%10;
			int j=y%10;
	        if(a==b) continue;
	        if(a==c) continue;
	        if(a==d) continue;
	        if(a==e) continue;
	        if(a==f) continue;
	        if(a==g) continue;
	        if(a==h) continue;
	        if(a==i) continue;
	        if(a==j) continue;
	        if(b==c) continue;
	        if(b==d) continue;
	        if(b==e) continue;
	        if(b==f) continue;
	        if(b==g) continue;
	        if(b==h) continue;
	        if(b==i) continue;
	        if(b==j) continue;
	        if(c==d) continue;
	        if(c==e) continue;
	        if(c==f) continue;
	        if(c==g) continue;
	        if(c==h) continue;
	        if(c==i) continue;
	        if(c==j) continue;
	        if(d==e) continue;
	        if(d==f) continue;
	        if(d==g) continue;
	        if(d==h) continue;
	        if(d==i) continue;
	        if(d==j) continue;
	        if(e==f) continue;
	        if(e==g) continue;
	        if(e==h) continue;
	        if(e==i) continue;
	        if(e==j) continue;
	        if(f==g) continue;
	        if(f==h) continue;
	        if(f==i) continue;
	        if(f==j) continue;
	        if(g==h) continue;
	        if(g==i) continue;
	        if(g==j) continue;
	        if(h==i) continue;
	        if(h==j) continue;
	        if(i==j) continue;
			cnt++;	
		}
	}
	cout<<cnt<<"\n";
	return 0;
}