1 条题解
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1
#include <bits/stdc++.h> using namespace std; const int MAXN = 100; const int MAXM = 10000; int n, m; // n个点 m条边 struct Edge { int u, v, w; }; Edge e[MAXM + 5]; int eCnt; bool cmp(Edge a, Edge b) { return a.w < b.w; } int fa[MAXN + 5]; int findFa(int x) { if (x == fa[x]) return x; return fa[x] = findFa(fa[x]); } int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> n; eCnt = 0; for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { eCnt++; cin >> e[eCnt].w; e[eCnt].u = i; e[eCnt].v = j; } } m = eCnt; // 排序 sort(e + 1, e + m + 1, cmp); // 并查集初始化 for (int i = 1; i <= n; i++) fa[i] = i; // kruskal/避开环 int ans = 0; int cnt = 0; for (int i = 1; i <= m; i++) { // e[i].u <-> e[i].v : e[i].w // 如果会构成环,就不选,否则就选 int faU = findFa(e[i].u); int faV = findFa(e[i].v); if (faU != faV) { fa[faU] = faV; ans += e[i].w; cnt++; } } if (cnt == n - 1) cout << ans << "\n"; else cout << "orz\n"; return 0; }
- 1
信息
- ID
- 569
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 4
- 标签
- (无)
- 递交数
- 44
- 已通过
- 23
- 上传者