1 条题解
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#include <bits/stdc++.h> using namespace std; const int MAXM = 20000; const int MAXN = 10000; int n, k, m; struct Edge { int u, v, p1, p2, id; }; Edge e[MAXM + 5]; // 存最大花费及方案 int ans; vector<pair<int, int>> plan; // 按 p1 排序 bool cmp1(Edge e1, Edge e2) { return e1.p1 < e2.p1; } // 按 p2 排序 bool cmp2(Edge e1, Edge e2) { return e1.p2 < e2.p2; } // 并查集 int fa[MAXN + 5]; int findFa(int x) { if (x == fa[x]) return x; return fa[x] = findFa(fa[x]); } int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> n >> k >> m; for (int i = 1; i <= m; i++) { cin >> e[i].u >> e[i].v >> e[i].p1 >> e[i].p2; e[i].id = i; } // 并查集初始化 for (int i = 1; i <= n; i++) fa[i] = i; // 记录答案 ans = 0; // 先建 k 条一级公路,挑小的建 sort(e + 1, e + m + 1, cmp1); for (int i = 1, cnt = 0; i <= m; i++) { int faU = findFa(e[i].u); int faV = findFa(e[i].v); if (faU != faV) { ans = max(ans, e[i].p1); fa[faU] = faV; plan.push_back({e[i].id, 1}); cnt++; if (cnt == k) break; } } // 然后剩下的用二级公路补 sort(e + 1, e + m + 1, cmp2); for (int i = 1; i <= m; i++) { int faU = findFa(e[i].u); int faV = findFa(e[i].v); if (faU != faV) { ans = max(ans, e[i].p2); fa[faU] = faV; plan.push_back({e[i].id, 2}); } } // 输出 cout << ans << "\n"; sort(plan.begin(), plan.end()); for (int i = 0; i < plan.size(); i++) cout << plan[i].first << " " << plan[i].second << "\n"; return 0; }
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信息
- ID
- 3096
- 时间
- 1000ms
- 内存
- 125MiB
- 难度
- 4
- 标签
- 递交数
- 15
- 已通过
- 8
- 上传者