1 条题解
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0
#include <bits/stdc++.h> using namespace std; int n, m; int a[105][105], b[105][105]; int main() { //输入 cin >> n >> m; for (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) cin >> a[i][j]; //转置: b[i][j] = a[j][i] for (int i = 1; i <= m; i++) for (int j = 1; j <= n; j++) b[i][j] = a[j][i]; //输出 for (int i = 1; i <= m; i++) { for (int j = 1; j <= n; j++) cout << b[i][j] << " "; cout << "\n"; } return 0; } /* a[1][1] a[1][2] a[2][1] a[2][2] a[3][1] a[3][2] a[1][1] a[2][1] a[3][1] a[1][2] a[2][2] a[3][2] b[1][1] b[1][2] b[1][3] b[2][1] b[2][2] b[2][3] */
- 1
信息
- ID
- 346
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 3
- 标签
- (无)
- 递交数
- 96
- 已通过
- 53
- 上传者