#P15180. [SWERC 2021] Antennas

[SWERC 2021] Antennas

题目描述

There are n n equidistant antennas on a line, numbered from 1 1 to n n . Each antenna has a power rating, the power of the i i -th antenna is pi p_i .

The i i -th and the j j -th antenna can communicate directly if and only if their distance is at most the minimum of their powers, i.e., ijmin(pi,pj) |i-j| \leq \min(p_i, p_j) . Sending a message directly between two such antennas takes 1 1 second.

What is the minimum amount of time necessary to send a message from antenna a a to antenna b b , possibly using other antennas as relays?

输入格式

Each test contains multiple test cases. The first line contains an integer t t ( 1t100000 1\le t\le 100\,000 ) — the number of test cases. The descriptions of the t t test cases follow.

The first line of each test case contains three integers n n , a a , b b ( 1a,bn200000 1 \leq a, b \leq n \leq 200\,000 ) — the number of antennas, and the origin and target antenna.

The second line contains n n integers p1,p2,,pn p_1, p_2, \dots, p_n ( 1pin 1 \leq p_i \leq n ) — the powers of the antennas.

The sum of the values of n n over all test cases does not exceed 200000 200\,000 .

输出格式

For each test case, print the number of seconds needed to trasmit a message from a a to b b . It can be shown that under the problem constraints, it is always possible to send such a message.

3
10 2 9
4 1 1 1 5 1 1 1 1 5
1 1 1
1
3 1 3
3 3 1
4
0
2

提示

In the first test case, we must send a message from antenna 2 2 to antenna 9 9 . A sequence of communications requiring 4 4 seconds, which is the minimum possible amount of time, is the following:

  • In 1 1 second we send the message from antenna 2 2 to antenna 1 1 . This is possible since 21min(1,4)=min(p2,p1) |2-1|\le \min(1, 4) = \min(p_2, p_1) .
  • In 1 1 second we send the message from antenna 1 1 to antenna 5 5 . This is possible since 15min(4,5)=min(p1,p5) |1-5|\le \min(4, 5) = \min(p_1, p_5) .
  • In 1 1 second we send the message from antenna 5 5 to antenna 10 10 . This is possible since 510min(5,5)=min(p5,p10) |5-10|\le \min(5, 5) = \min(p_5, p_{10}) .
  • In 1 1 second we send the message from antenna 10 10 to antenna 9 9 . This is possible since 109min(5,1)=min(p10,p9) |10-9|\le \min(5, 1) = \min(p_{10}, p_9) .