1 条题解
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0
#include <bits/stdc++.h> using namespace std; int n, m; int a[112345]; //看看如果每段和都不超过 maxSum,最少分成的段数是否不超过 M。 bool check(int maxSum) { int cnt = 1; int nowSum = 0; for (int i = 1; i <= n; i++) { if (a[i] > maxSum) return false; if (nowSum + a[i] <= maxSum) nowSum += a[i]; else { cnt++; nowSum = a[i]; } } return cnt <= m; } int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> n >> m; for (int i = 1; i <= n; i++) cin >> a[i]; int l = 0; int r = 1000000000; int ans = -1; while (l <= r) { int mid = (l + r) / 2; if (check(mid)) { ans = mid; r = mid - 1; //调整上限,看能不能更小 } else l = mid + 1; } cout << ans << "\n"; return 0; }
- 1
信息
- ID
- 655
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 5
- 标签
- 递交数
- 84
- 已通过
- 32
- 上传者